How do you distinguish the basicity levels for amines? Like what makes an amine a weaker/stronger base? And why? (The more the lone electron pair of N is involved in conjugation, the less basic it is. Also, sp2-hybridized nitrogen is less basic than sp3-hybridized nitrogen, because the lone pair has lower energy and, therefore, less reactive. - GS).
This blog is a learning resource for undergraduate students studying organic chemistry. It consists of a database of actual questions and answers about organic chemistry collected by a chemistry professor teaching the subject.
Topics
- Halides-alcohols-ethers (94)
- Conjugation (60)
- Alkenes-alkynes (51)
- Carboxylic acid derivatives (39)
- Structure-bonding (39)
- Aldehydes and ketones (36)
- Alkanes-cycloalkanes (31)
- Stereochemistry (27)
- Spectroscopy (21)
- Acids-bases (19)
- Amines (18)
- Useful links (2)
Thursday, October 29, 2015
Wednesday, October 28, 2015
Resonance structures provide a means to show electron delocalization which in turn stabilizes the structure, right? (Yes. - GS). So for simplicity’s sake this means that structures that can be demonstrated using resonance structures for it are more stable than a similar molecule that cant form resonance, right? (Correct. - GS).
^^Could you explain why electron delocalization would be seen as stabilizing if a carbocation or anion would constantly result from this formation? (Electrons will have more space and more opportunities to lower their energy. Same on the math language: there will be more coefficients to optimize in the linear combination of atomic orbitals - GS). Wouldn't a neutral structure with no charged carbons be more stable than one that would observe resonance characteristics? (The neutral structure will be most contributing. - GS).
How do you know which reaction product is less stable? For example, in the addition of HCl to conjugated dienes, the major product formed is 1,2-addition results in major product which is less stable than 1,4-addition. Is 1,4- just typically more stable? (Yes, because of a more substituted C=C bond - GS).
Are halogens inductive acceptors and resonance donors? (Yes, but Cl, Br, and I are also resonance acceptors because of the empty d-orbitals - GS). So, are halogens resonance donors and resonance acceptors? (No. They are resonance donors and inductive acceptors. Cl, Br, and I are also resonance acceptors because of the empty d-orbitals - GS).
Monday, October 26, 2015
Thursday, October 15, 2015
Why would a compound that mimics a plant growth hormone be used as a commercial lawn fertilizer? Wouldn't that just cause the plant to grow more quickly? (Yes, it is not a nutrient. In larger concentrations, they are used as herbicides, because they make the plant grow so unnaturally fast, that the plant dies quickly. - GS).
Brominated organic molecules are used commercially as flame retardants, why is that? (I thinks that the three following contributors are important: 1. Br-containing molecules act as traps for free radicals, so they speed up free radical chain termination; 2. Non-combustible molecules (HBr and Br2) are produced, and they extinguish fire like carbon dioxide; 3. Bromine does not bond well with oxygen, so the energy spend on breakage of the C-Br and C-H is not compensated enough by a relatively weak H-Br bond. - GS).
Alcohols are a weak acid, which is why we can intake alcohol without experiencing severe irritation, right? (Ethanol causes irritation when its concentration exceeds 40%, which corresponds to the hydrate of ethanol. Above this concentration, ethanol acts as a drying agent. It was a part of M.S. thesis of Dmitri Mendeleev, which is much less known than his periodic table of elements. - GS). But just out of curiosity is the fact that alcohol is indeed a acid (even though its weak) one of the reasons alcoholics experience extreme symptoms such as ulcers (which could be described as an erosion or “break” of intestinal lining, etc.)? Is that alright to observe those effects in that manner, or is that side effect due to a different characteristic altogether? (No. Those adverse reactions are mostly because of oxidation of ethanol to a toxic ethanal. - GS).
So is it wrong to think that more polar molecules often have lower boiling points if the molecular size is similar? (Polar molecules have higher boiling points because of stronger electrostatic intermolecular interaction. - GS). Larger molecules have higher boiling points? (Yes, because of stronger Van-der-Waals intermolecular interaction. - GS).
Wednesday, October 14, 2015
Could you go over how the free radicals one more time? I still don’t fully understand it. Thanks (Ok. Please, also review this: http://ochem.orgfree.com/SR.html - GS).
Hi Dr. Sereda, I was wondering if you could explain a little better the relationships with the boiling points, polarity, molecular size, and molecular shape? (Molecular shape determines polarity. Polarity and molecular size, and again shape, determine intermolecular interactions. Intermolecular interactions determine the boiling points. - GS).
Is a rearrangement reaction going to take place when the conditions are in line with a SN1 reaction? Because a rearrangement reaction is where a carbocation gets reformed into something more stable and in an SN1 reaction is where one of the steps to get to the product is through a carbocation intermediate. (Yes. SN1 and any other reaction involving carbocations can be complicated by carbocation rearrangements. - GS).
Dr. Sereda would you mind explaining how we differentiate between SN1 (http://ochem.orgfree.com/sn1.html - GS) and SN2 (http://ochem.orgfree.com/sn2.html - GS). reactions? (See the links that I inserted to your question. - GS).
Tuesday, October 6, 2015
Different compounds can be expressed in terms of optically pure compounds as (+) or (-), could you explain how we are supposed to differentiate between when its (+) or negative? Is it simply in regards to the rotation it expresses so it has a negative then it would be because it is the enantiomer of the optical compound? (If a compound has positive rotation, its enantiomer will be for sure negative, and vice versa. You cannot determine an absolute value or sign of rotation just by the structure. An experiment is needed. - GS).
^^Sorry this may be naive, but what do we gain by knowing if its (+) and (-)? (It is part of a compound’s identity and purity, like its melting point. - GS).
^So you could use it as another way to identify a compound? (Yes, and evaluate its purity, which also embraces monitoring chemical reactions of that compound. Mutarotation is a great example. - GS).
Monday, October 5, 2015
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