What does cyclic mean? (It means, that some atoms are connected by chemical bonds to at least one chain that has no ends. - GS).
This blog is a learning resource for undergraduate students studying organic chemistry. It consists of a database of actual questions and answers about organic chemistry collected by a chemistry professor teaching the subject.
Topics
- Halides-alcohols-ethers (94)
- Conjugation (60)
- Alkenes-alkynes (51)
- Carboxylic acid derivatives (39)
- Structure-bonding (39)
- Aldehydes and ketones (36)
- Alkanes-cycloalkanes (31)
- Stereochemistry (27)
- Spectroscopy (21)
- Acids-bases (19)
- Amines (18)
- Useful links (2)
Monday, October 31, 2016
I know you touched on this at the end of class, but i am still confused. When trying to determine whether or not hydrogen bonds will form between a molecule and water we look for lone pairs, correct?? (Yes. - GS). What about when trying to determine if a molecule will form hydrogen bonds with itself?? (It happens when the molecule contains a both H-bond donor, and a H-bond acceptor. - GS).
What is the difference between alkylation and acylation of amines? Could you please go through an example of each? (Alkylation is introduction of an alkyl group to the amine’s nitrogen. Example - preparation of lecithin from methyl iodide. Acylation is introduction of an acyl group to the amine’s nitrogen. Example - synthesis of acetaminophen from para-aminophenol. - GS).
Wednesday, October 26, 2016
What is n in 4n+2? I understand that it is an integer but what number does it represent? Principal Quantum number? (No, it comes from the mathematical definition of an odd number of orbitals (2n+1). - GS). It is still not clear. (Each orbitals holds 2 electron, so the number of electrons = 2X(2n+1) - 4n+2. - GS).
Tuesday, October 25, 2016
Can you please review how to determine if a compound is aromatic or not depending on the number of conjugated electrons? I understand how to count the number of conjugated electrons but am unsure of how that relates to aromaticity. Thanks (An aromatic system must contain 4n+2 electrons (n=0,1,2,....) in a cyclic conjugation (uninterrupted by sp3-hybridized atoms. - GS).
Why is having a donor in the Meta position so unfavorable? (Since the sigma-complex has the formal positive charge distributed between ortho- and para-positions, the groups at those positions have the strongest effect on the reaction, so the donor speeds up ortho- and para-substitution much more than meta-substitution. - GS).
To clarify- if you have an incoming substituents in the metha or ortho position, there is a strong influence and if you have an incoming substituent in the ortho position there is little influence? (No. Since the sigma-complex has the formal positive charge distributed between ortho- and para-positions, the groups at those positions have the strongest effect on the reaction.The incoming substituent has almost no influence, because it attaches to an sp3-carbon with no formal charge - GS).
Monday, October 24, 2016
So far we learned about ortho and para positions but do compounds ever go to the meta position and if so when does that happen? (Electrophiles always enter the meta-position,, but preferably - when the existing group has no donating effects. - GS). Also can you go over why meta isn’t as favorable as ortho or para please, I’m still confused why it isn’t? (The sigma-complex has the positive charge distributed over the ortho- and para-positions, so it is stabilized better by ortho- and para- electron-donating substituents, which makes the ortho- and para-orientation preferred. Ortho- and para-substituents with no electron-donating effects are are having trouble withdrawing electrons from the positively-charged ortho- and para-positions, which makes ortho- and para-orientation unfavorable, so the meta-substitution is preferred. - GS).
Can you go over another example of the pi-complex and sigma-complex mechanisms? I don’t really know the distinction between the two quite yet. Thanks!! (They are steps of the same mechanism of aromatic electrophilic substitution: http://ochem.orgfree.com/SEAr.html - GS).
Friday, October 21, 2016
How do we know if lone pairs participate in regards to aromatic and antiaromatic compounds? (It participates if it can be perpendicular to the plane of the ring and, therefore, align with the pi-system. It will always happen if that space is not already occupied by a p-orbital of the pi-system. - GS).
Wednesday, October 19, 2016
Tuesday, October 11, 2016
I understand that hydroboration followed by oxidation is used when we need to perform hydration of a double bond against markovnikov’s rule, however, at what point is the markovnikov’s rule broken? According to markovnikov, the halogen of the hydrogen halide attaches to the carbon of alkene bearing the fewer number of hydrogen and greater number of carbons, so does this mean the rule is broken when the conditions are changed as to where it attaches? (That was the original rule formulation of Markovnikov’s himself. Now, we understand the rule broader: instead of halogen, it can be any negative part of the reagent. The rule usually works if addition proceeds through a carbocation, which is not the case for hydroboration. - GS).
Sunday, October 9, 2016
Does the SP3 bond break when its fragments are rotated? (There are no sp3 bonds. - GS). Also, can you please give an explanation on this concept. Thanks! (Sigma-bonds do not break, because the bond-forming orbitals (may involve sp3-orbitals), overlap in only one area. Pi-bonds break, because the bond-forming p-orbitals overlap in two areas, which have to disconnect during the rotation.. - GS).
Thursday, October 6, 2016
When selecting R or S configuration, I know that we 1. Rank substituents by highest priority (highest atomic mass) 2. Find out which way priority is decreasing 3. If priority is decreasing clockwise, then R configuration… If priority is decreasing counterclockwise, then S configuration 4. Change R configuration to S configuration, or vice-versa, if lowest priority group is pointing to the front….. I understand all of this, however, I always get confused when the lowest priority group is neither pointing towards you or away from you…. Do we still flip the configuration if the lowest priority group is in the plane of the paper? (Flip the lowest in priority group, which is in the plane of paper with the group behind paper, determine configuration as usual, and flip your answer. - GS). Or do we instead have to rotate the molecule in our minds in order to get the lowest priority facing away, and then go ahead and figure out the configuration? Spasibo. (This will also work. Choose either method, depending on your individual strengths. - GS). Your advice to flip the lowest priority, which is in the plane of paper, with the group behind the paper, determine configuration, and flip the answer sounds much better. That really cleared things up. Thank you!!
Actually, please explain the entire concept of Solvent Effects on Nucleophilicity. Please be specific on what we need to know. Thanks. (As opposed to protic solvents, aprotic solvents selectively solvate cations, leaving anions “untamed”. This reverses the nucleophilicity trend of anions in groups, such is from F to I - GS).
Wednesday, October 5, 2016
Tuesday, October 4, 2016
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