Why does having a destabilized nucleophile in an SN2 reaction decrease the free energy of activation? (Because the transition state retains its energy, so the activation barrier is lower. - GS).
This blog is a learning resource for undergraduate students studying organic chemistry. It consists of a database of actual questions and answers about organic chemistry collected by a chemistry professor teaching the subject.
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Wednesday, March 23, 2016
How does a polar, protic solvent reduce the free energy of activation and stabilize an intermediate in an SN1 reaction? (By solvation of the very polar transition state - GS). And, why does a stabilized intermediate reduce the energy barrier? (Because the less polar starting compound is not stabilized as efficiently as the transition state - GS).
Tuesday, March 15, 2016
Dr. Sereda, I was looking over some of the previous year’s quizzes and in the preparation of 5-methyl-2-hexyne from propyne, what would be the nucleophile? Would it be the same as the alkylating agent? Thanks. (The nucleophile is deprotonated alkyne, which attacks the alkylating agent and kicks out the leaving group from it. Overall, it results in the introduction of the alkyl group to the alkyne. - GS).
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